Friday, May 18th, 2007<\/p>\n
Think about it this way\u2026 Friday, May 18th, 2007 Think about it this way\u2026 the reactants (left hand side) go on to make the products (right hand side) Imagine that this reaction proceeds VIA the elements in their standard states, (according to Hess\u2019s law we can go any way we want providing that we get to the desired products) First […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9,11],"tags":[44,85],"class_list":["post-17","post","type-post","status-publish","format-standard","hentry","category-organic","category-physical","tag-enthalpy-of-formation","tag-reaction-enthalpy"],"_links":{"self":[{"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/posts\/17","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/comments?post=17"}],"version-history":[{"count":0,"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/posts\/17\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/media?parent=17"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/categories?post=17"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.ibchem.com\/blog\/wp-json\/wp\/v2\/tags?post=17"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nthe reactants (left hand side) go on to make the products (right hand side)
\nImagine that this reaction proceeds VIA the elements in their standard states, (according to Hess\u2019s law we can go any way we want providing that we get to the desired products)
\nFirst of all, the reactants have to return to their elements. This process is the opposite of the enthalpy of formation, i.e. the negative or reverse of delta Hf = -delta Hf
\nThe products are then formed from the elements – this is simply the enthalpy of formation, i.e. + deltaHf
\nSo, if you sum these two processes to go from reactants to products you have:
\nReaction enthalpy = – delta Hf(reactants) + deltaHf(products)
\nrearrange this to get:
\nReaction enthalpy = deltaHf(products) – delta Hf(reactants)Идея за подарък<\/a><\/font>икони<\/a><\/font><\/p>\n","protected":false},"excerpt":{"rendered":"